How do you balance the equation in chemistry on your own 9.4c?

You start out with:

H3PO4 + Mg(OH)2 --> Mg3(PO4)2 + H2O

Stay away from the H's and O's at first, because they appear in multiple substances on at least one side of the equation. Thus, we start with P and Mg. To balance P, multiply H3PO4 by 2:


2H3PO4 + Mg(OH)2 --> Mg3(PO4)2 + H2O

To balance Mg, multiply Mg(OH)2 by 3:

2H3PO4 + 3Mg(OH)2 --> Mg3(PO4)2 + H2O

Now look at H's, because they appear only once on the products side. There is 2x3 + 3x2 = 12 H's, so multiply H2O by 6:

2H3PO4 + 3Mg(OH)2 --> Mg3(PO4)2 + 6H2O

Now the O's are balanced, too (2x4 + 3x2 = 14 on reactants side, 4x2 +6x1 = 14 on products side).

Tags: Chemsitry
Last update:
2019-01-31 18:58
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